# How do you solve 3(3t + 3) = 3(-3t + (-39))?

Jul 23, 2015

You isolate all the terms that contain $t$ on one side of the equation.

#### Explanation:

So, start by looking at your starting equation

$3 \cdot \left(3 t + 3\right) = 3 \cdot \left[- 3 t + \left(- 39\right)\right]$

This is equivalent to

$\cancel{3} \cdot \left(3 t + 3\right) = \cancel{3} \cdot \left(- 3 t - 39\right)$

To get all the terms that contain the variable $t$ on one side of the equation, add $3 t$ on both sides to get

$3 t + 3 + 3 t = \cancel{- 3 t} + \cancel{3 t} - 39$

$6 t + 3 = - 39$

Now add $- 3$ on both sides of the equation to isolate the term that contsins $t$ on one side

$6 t + \cancel{3} + \cancel{- 3} = - 39 - 3$

$6 t = - 42$

This means that $t$ is equal to

$t = - \frac{42}{6} = \textcolor{g r e e n}{- 7}$