How do you solve #3(3x+1)-(x-1)=6(x+10)#?

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Answer 1 · 2016-04-28T16:32:02

#x = 28#

#3 ( 3x+1) - (x-1) = 6 (x+10)#

#3 * ( 3x)+ 3 * (1) - x + 1 = 6 * (x) + 6 * (10)#

#9x+ 3 - x + 1 = 6 x + 60#

#9x - x + 3 + 1 = 6 x + 60#

#8x + 4 = 6 x + 60#

#8x -6x = 60 - 4#

#2x = 56#

#x = 56/2#

#x = 28#