Question

How do you solve `3( - 3x + 5) - 3x - 4= - 1`?

Answer 1

`x=1`

Explanation:

First step is to distribute the bracket on left side of the equation.

`-9x+15-3x-4=-1`

collect like terms on left side.

`rArr-12x+11=-1`

subtract 11 from both sides.

`-12xcancel(+11)cancel(-11)=-1-11`

`rArr-12x=-12`

To solve for x, divide both sides by - 12.

`(cancel(-12) x)/cancel(-12)=(-12)/(-12)`

`rArrx=1" is the solution"`