Question

How do you solve `3/4``(2/3)^x = 4/27`?

Answer 1

`x=4`

Explanation:

`3/4(2/3)^x=4/27`

`hArr(2/3)^x=4/27xx4/3=16/81` or

`(2/3)^x=(2xx2xx2xx2)/(3xx3xx3xx3)`

`(2/3)^x=2^4/3^4=(2/3)^4`

`x=4`