# How do you solve #3-4(2k-5)=71# using the distributive property?

##### 2 Answers

See the entire solution process below:

#### Explanation:

First, expand the term in parenthesis on the left side of the equation by multiplying each term within the parenthesis by

Next, subtract

Now, divide each side of the equation by

#### Explanation:

distribute the bracket to begin with.

#3-8k+20=71#

#rArr-8k+23=71# subtract 23 from both sides.

#-8kcancel(+23)cancel(-23)=71-23#

#rArr-8k=48# divide both sides by - 8

#(cancel(-8) k)/cancel(-8)=48/(-8)#

#rArrk=-6#

#color(blue)"As a check"# Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#"left side "=3-4((2xx-6)-5)#

#color(white)(left side)=3-(4xx(-17))#

#color(white)(left side)=3-(-68)=3+68=71#

#rArrk=-6" is the solution"#