Question

How do you solve `3/4(2x+3)^2-9=0`?

Answer 1

`x=(-3+-2sqrt3)/2`

Explanation:

`3/4(2x+3)^2-9=0`
`=>3/4(2x+3)^2=9`
`=>(2x+3)^2=9xx4/3=12`
`=>(2x+3)=+-sqrt(3*2^2) =+-2sqrt3`
`=>2x=(-3+-2sqrt3)`
`=>:.x=(-3+-2sqrt3)/2`