How do you solve #3/4(4x+8)=-12# using the distributive property?

1 Answer
Jan 22, 2017

Answer:

See the entire solution process below:

Explanation:

First, we distribute the #color(red)(3/4)# term across each of the terms within the parenthesis:

#(color(red)(3)/color(red)(4) xx 4x) + (color(red)(3)/color(red)(4) xx 8) = -12#

#(color(red)(3)/cancel(color(red)(4)) xx color(red)(cancel(color(black)(4)))x) + (color(red)(3)/cancel(color(red)(4)) xx color(red)(cancel(color(black)(8)))2) = -12#

#3x + 6 = -12#

Next, subtract #color(red)(6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#3x + 6 - color(red)(6) = -12 - color(red)(6)#

#3x + 0 = -18#

#3x = -18#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#(3x)/color(red)(3) = -18/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = -6#

#x = -6#