How do you solve #3= 4( x - 2) + 3- 2x#?

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Answer 1 · 2018-04-25T18:32:13

# x = 4#

Start with the right part and solve the parentheses

#4(x-2) = 4x - 8#

Rewrite your equation

#3 = 4x -8 + 3 -2x#

Subtract #3# from both sides, you have

#0 = 4x - 8 - 2x#

#0 = 2x -8#

Add #8# to both sides

#8 = 2x#

Divide all by #2#

#x = 4#