How do you solve #3/4 y -1/2 y -5=7#?

1 Answer
May 11, 2016

#y = 48#

Explanation:

This is an equation with fractions. We can get rid of the denominators by multiplying each term by the LCM of the denominators, (which is 4).

#3/4y -1/2y -5 = 7 rArr # #color(red)4 xx 3/4y - color(red)4 xx1/2y -color(red)4 xx5 = color(red)4 xx7#

#cancelcolor(red)4 xx 3/cancel4y - color(red)cancel4^2 xx1/cancel2y -color(red)4 xx5 = color(red)4 xx7#

#3y - 2y -20 = 28#

#y = 48#