How do you solve -3(4x+3)+4(6x+1)=43?

Mar 17, 2018

$x = 4$

Explanation:

$- 3 \left(4 x + 3\right) + 4 \left(6 x + 1\right) = 43$

Opening the brackets:

$- 12 x - 9 + 24 x + 4 = 43$

Combine like terms:

$- 12 x + 24 x - 9 + 4 = 43$

$12 x - 5 = 43$

Isolate the x by adding 5:

$12 x - 5 + 5 = 43 + 5$

$12 x = 48$

Isolate the x completely by dividing both sides by 12:

$\frac{\cancel{12} x}{\cancel{12}} = \frac{48}{12}$

$x = 4$