How do you solve #-3(4x+3)+4(6x+1)=43#?

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Answer 1 · 2018-03-17T01:08:14

#x=4#

#-3(4x+3)+4(6x+1)=43#

Opening the brackets:

#-12x-9+24x+4=43#

Combine like terms:

#-12x+24x-9+4=43#

#12x-5=43#

Isolate the x by adding 5:

#12x-5+5=43+5#

#12x=48#

Isolate the x completely by dividing both sides by 12:

#(cancel(12)x)/cancel12=48/12#

#x=4#