How do you solve #-3/(4x) + 3/8 = 27/32#?

2 Answers
Mar 24, 2018

Answer:

#x = -1.6#

Explanation:

#-3/(4x) + 3/8 = 27/32#
#-3/(4x) = 27/32- 3/8#
#-3/(4x) = 27/32 - 12/32#
#-3/(4x) = 15/32#
By cross-multiplication:
#4x*15 = -3*32#
#60x = -96#
#x = -96/60#
#x = -1.6#

Mar 24, 2018

Answer:

#x=-8/5#

Explanation:

Before we do anything, we need to get a common denominator of #32#.

#-3/4x=-24/32x# (multiplying top and bottom by 8)

#3/8=12/32# (multiplying top and bottom by 4)

#27/32# will stay the same

Thus, we have

#-24/32x+12/32=27/32#

We can subtract #12/32# from both sides to get

#-24/32x=15/32#

We can cross multiply to get:

#x=(-24*cancel32)/(cancel32*15)#

Since the #32#s will cancel, we're left with:

#(-24)/(15)#

Which can be simplified to #x=-8/5#