How do you solve #3 ^(-4x+4) = 9#?

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Answer 1 · 2016-05-23T07:55:41

#x=1/2#

#3^(-4x+4)=9#

#3^(-4x) *3^4=3^2#

#3^(-4x)=(3^2)/(3^4)#

#3^(-4x)=3^2*3^-4#

#color(red)(3)^(-4x)=color(red)(3)^-2#

#"Both side of equation has the same base value"#

#-4x=-2#

#x=2/4#

#x=1/2#