How do you solve #3.5^(5x) = 2650#?

1 Answer
May 16, 2016

I found: #x=1.2584#

Explanation:

We could first take the natural log of both sides:
#ln(3.5)^(5x)=ln(2650)#
then get rid of the exponent in the first using a property of logs to write:
#5xln(3.5)=ln(2650)#
rearrange:
#x=ln(2650)/(5ln(3.5))=1.2584#