Question

How do you solve `3.5^(5x) = 2650`?

Answer 1

I found: `x=1.2584`

Explanation:

We could first take the natural log of both sides:
`ln(3.5)^(5x)=ln(2650)`
then get rid of the exponent in the first using a property of logs to write:
`5xln(3.5)=ln(2650)`
rearrange:
`x=ln(2650)/(5ln(3.5))=1.2584`