Question

How do you solve `3(5j + 2) = 2(3j - 6)`?

Answer 1

`j=-2`

Explanation:

Distribute the brackets on both sides of the equation.

`rArr15j+6=6j-12`

Collect terms in j on the left side and numeric values on the right side.

subtract 6j from both sides.

`15j-6j+6=cancel(6j)cancel(-6j)-12`

`rArr9j+6=-12`

subtract 6 from both sides.

`9jcancel(+6)cancel(-6)=-12-6`

`rArr9j=-18`

To solve for j, divide both sides by 9

`(cancel(9) j)/cancel(9)=(-18)/9`

`rArrj=-2" is the solution"`

`color(blue)"As a check"`

substitute j = -2 into the equation and if the left side equals the right side then it is a solution.

`"left side " =3(5xx-2+2)=3(-8)=-24`

`"right side " =2(3xx-2-6)=2(-12)=-24`

`rArrj=-2" is the solution"`