How do you solve #- 3/5y + 7 = - 8#?

1 Answer
Nov 5, 2015

#y = 75/3# or #y = 25#, simplified.

Explanation:

In this equation, your end goal is to get #y# by itself.

Your first step is to get #y# isolated on one side. To do this, you would use the #"subtraction property of equality"#. You will subtract #7# from both sides to cancel out the left side #7# and leave #y# by itself. #-3/5y + 7 = -8 => -3/5y + 0 = -15#

Now you have #-3/5y = -15# and you want to get y completely by itself. To do this you would use the #"multiplication property of equality"#, and multiply by the #"reciprocal"# to make the #-3/5# to 1.
#-3/5y*(-5/3)=-15/1*(-5/3)#

Doing this will give you #y = 75/3# which reduces down to #y=25#.