How do you solve #3.6t+6-2.5t=8#?

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Answer 1 · 2017-05-03T20:06:17

See the solution process below:

First, group and combine like terms on the left side of the equation:

#3.6t + 6 - 2.5t = 8#

#3.6t - 2.5t + 6 = 8#

#(3.6 - 2.5)t + 6 = 8#

#1.1t + 6 = 8#

Next, subtract #color(red)(6)# from each side of the equation to isolate the #t# term while keeping the equation balanced:

#1.1t + 6 - color(red)(6) = 8 - color(red)(6)#

#1.1t + 0 = 2#

#1.1t = 2#

Now, divide each side of the equation by #color(red)(1.1)# to solve for #x# while keeping the equation balanced:

#(1.1t)/color(red)(1.1) = 2/color(red)(1.1)#

#(color(red)(cancel(color(black)(1.1)))t)/cancel(color(red)(1.1)) = 1.bar81#

#t = 1.bar81#