How do you solve #(3/7)x+2=4#?

1 Answer
Feb 11, 2017

See the entire solution process below:

Explanation:

Step 1) Subtract #color(red)(2)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#(3/7)x + 2 - color(red)(2) = 4 - color(red)(2)#

#(3/7)x + 0 = 2#

#(3/7)x = 2#

Step 2) Multiply each side of the equation by #color(red)(7)/color(blue)(3)# to solve for #x# while keeping the equation balanced:

#color(red)(7)/color(blue)(3) xx (3/7)x = color(red)(7)/color(blue)(3) xx 2#

#cancel(color(red)(7))/cancel(color(blue)(3)) xx (color(blue)(cancel(color(black)(3)))/color(red)(cancel(color(black)(7))))x = 14/color(blue)(3)#

#x = 14/3#