# How do you solve 3/8m + 7/8 = 2m?

Mar 2, 2016

You can do this in several ways. I usually try to get rid of fractions first.

#### Explanation:

Multiply everything by $8$:
$\to \cancel{8} \cdot \frac{3}{\cancel{8}} m + \cancel{8} \cdot \frac{7}{\cancel{8}} = 8 \cdot 2 m$

$\to 3 m + 7 = 16 m$

Now get the $m$'s to one side and the numbers to the other:

$- 3 m$ on both sides:

$\to \cancel{3 m} - \cancel{3 m} + 7 = 16 m - 3 m$

$\to 13 m = 7 \to m = \frac{7}{13}$

Mar 2, 2016

$m = \frac{7}{13}$

#### Explanation:

$\frac{3}{8} m + \frac{7}{8} = 2 m$

Multiply each term by $8$ to get rid of the denominator

$\rightarrow \cancel{8} \cdot \frac{3}{\cancel{8}} m + \cancel{8} \cdot \frac{7}{\cancel{8}} = 8 \cdot 2 m$

$\rightarrow 3 m + 7 = 16 m$

Rewrite

$\rightarrow 16 m = 3 m + 7$

$\rightarrow 16 m - 3 m = 7$

$\rightarrow 13 m = 7$

$\Rightarrow m = \frac{7}{13}$