# How do you solve 3>h/-2 and graph the solutions?

Oct 4, 2017

See a solution process below:

#### Explanation:

Multiply each side of the inequality by $\textcolor{b l u e}{- 2}$ to solve for $h$ while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:

$\textcolor{b l u e}{- 2} \times 3 \textcolor{red}{<} \textcolor{b l u e}{- 2} \times \frac{h}{-} 2$

$- 6 \textcolor{red}{<} \cancel{\textcolor{b l u e}{- 2}} \times \frac{h}{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{- 2}}}}$

$- 6 \textcolor{red}{<} h$

We can state the solution in terms of $h$ by reversing or "flipping" the entire inequality:

$h > - 6$

To graph this we will draw a vertical line at $- 6$ on the horizontal axis.

The line will be a dashed line because the inequality operator does not contain an "or equal to" clause.

We will shade to the right side of the line because the inequality operator contains a "greater than" clause:

graph{x>=-6 [-10, 10, -5, 5]}