How do you solve #3(p+2)-7p=18#?

1 Answer
Feb 8, 2017

Answer:

See the entire solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation:

#(3 xx p) + (3 xx 2) - 7p = 18#

#3p + 6 - 7p = 18#

Next, group and combine like terms on the left side of the equation:

#3p - 7p + 6 = 18#

#(3 - 7)p + 6 = 18#

#-4p + 6 = 18#

Then, subtract #color(red)(6)# from each side of the equation to isolate the #p# term while keeping the equation balanced:

#-4p + 6 - color(red)(6) = 18 - color(red)(6)#

#-4p + 0 = 12#

#-4p = 12#

Now, divide each side of the equation by #color(red)(-4)# to solve for #p# while keeping the equation balanced:

#(-4p)/color(red)(-4) = 12/color(red)(-4)#

#(color(red)(cancel(color(black)(-4)))p)/cancel(color(red)(-4)) = -3#

#p = -3#