How do you solve #(3(t-1/3))/2-4=6#?

1 Answer
May 15, 2018

Answer:

#t=7#

Explanation:

#(3(t-1/3))/2-4=6#
we want to isolate t

since the term containing t has 4 subtracted from it, we add 4 to both sides

adding 4 to both sides:
#(3(t-1/3))/2=10#

multiply both sides by 2 to get
#3(t-1/3)=20#

the term containing t is being multiplied by 3, so we can divide both sides by 3 to get

#(t-1/3)=20/3#

finally, #1/3# is being subtracted from t so we can add #1/3# to both sides to get

t = #21/3=7#