# How do you solve (3(t-1/3))/2-4=6?

May 15, 2018

$t = 7$

#### Explanation:

$\frac{3 \left(t - \frac{1}{3}\right)}{2} - 4 = 6$
we want to isolate t

since the term containing t has 4 subtracted from it, we add 4 to both sides

$\frac{3 \left(t - \frac{1}{3}\right)}{2} = 10$

multiply both sides by 2 to get
$3 \left(t - \frac{1}{3}\right) = 20$

the term containing t is being multiplied by 3, so we can divide both sides by 3 to get

$\left(t - \frac{1}{3}\right) = \frac{20}{3}$

finally, $\frac{1}{3}$ is being subtracted from t so we can add $\frac{1}{3}$ to both sides to get

t = $\frac{21}{3} = 7$