How do you solve 3(x + 1) = -2(x - 1) + 6?

May 8, 2016

$x = 1$

Explanation:

$3 \left(x + 1\right) = - 2 \left(x - 1\right) + 6$

$3 \cdot \left(x\right) + 3 \cdot \left(1\right) = - 2 \cdot \left(x\right) + \left(- 2\right) \cdot \left(- 1\right) + 6$

$3 x + 3 = - 2 x + 2 + 6$

$3 x + 2 x = 2 + 6 - 3$

$5 x = 5$

$x = \frac{5}{5}$

$x = 1$