How do you solve $3(x + 1) = -2(x - 1) + 6$ ?

Question

1469 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-08T17:50:09

$x= 1$

$3(x+1) = - 2(x - 1)+6$

$3 * (x) + 3 * (1) = - 2 * (x) + (-2) * ( - 1)+6$

$3x + 3 = - 2x + 2+6$

$3x + 2x = 2+6-3$

$5x = 5$

$x = 5 / 5$

$x= 1$

How do you solve 3(x + 1) = -2(x - 1) + 63(x + 1) = -2(x - 1) + 6?