How do you solve #3^(x+1) * 2^(x-2)= 21#?

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Answer 1 · 2015-11-15T02:14:39

Use law of exponents to simplify

#3^x3xx2^x/2^2=21#

#(3xx2)^x(3/4)=21#

#6^x=28#

Next, use the property of logs ...

#xlog6=log28#

#x=log28/log6~~1.86#

hope that helped