# How do you solve 3(x+1)(4/3)= 48 and find any extraneous solutions?

Jul 18, 2016

First step is to get rid of the $3$'s:

#### Explanation:

$\cancel{3} \left(x + 1\right) \left(\frac{4}{\cancel{3}}\right) = 48 \to$

And now the $4$'s:
$\cancel{4} \left(x + 1\right) = \cancel{4} \cdot 12 \to$

So we have $x + 1 = 12 \to x = 11$

We made no simplifications that are "under caution" (like dividing by $x$), so there are no extraneous solutions.