Question

How do you solve `3(x+1)(4/3)= 48` and find any extraneous solutions?

Answer 1

First step is to get rid of the `3`'s:

Explanation:

`cancel3(x+1)(4/cancel3)=48->`

And now the `4`'s:
`cancel4(x+1)=cancel4*12->`

So we have `x+1=12->x=11`

We made no simplifications that are "under caution" (like dividing by `x`), so there are no extraneous solutions.