# How do you solve 3(x-1)-4(x-3)=0?

Apr 16, 2018

$x = 9$

#### Explanation:

$3 \left(x - 1\right) - 4 \left(x - 3\right) = 0$

$\left(3\right) \left(x\right) + \left(3\right) \left(- 1\right) + \left(- 4\right) \left(x\right) + \left(- 4\right) \left(- 3\right) = 0$

$3 x - 3 - 4 x + 12 = 0$

$- x + 9 = 0$

Subtract $9$ on both sides

$- x + 9 - 9 = 0 - 9$

$- x = - 9$

Multiply both sides by $- 1$

$- x \times - 1 = - 9 \times - 1$

$x = 9$