How do you solve #3(x-1)-4(x-3)=0#?

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Answer 1 · 2018-04-16T01:52:09

#x=9#

#3(x-1)-4(x-3)=0#

Start with the distributive property

#(3)(x)+(3)(-1)+(-4)(x)+(-4)(-3)=0#

#3x - 3 - 4x + 12 =0#

#-x + 9 = 0#

Subtract #9# on both sides

#-x + 9 - 9 = 0 - 9#

#-x = -9#

Multiply both sides by #-1#

#-x xx-1 = -9 xx -1#

#x = 9#