Question

How do you solve `3(x^2-2x+5) -2(3x-5) = 4(x^2-x-5)-(x^2+3)`?

Answer 1

`x=6`

Explanation:

First, expand each expression.
`3(x^2−2x+5)−2(3x−5)=4(x^2−x−5)−(x^2+3)`
`3x^2−6x+15−6x+10=4x^2−4x−20−x^2-3`

Next, combine everything in one side.
`3x^2−6x+15−6x+10=4x^2−4x−20−x^2-3`
`3x^2−6x+15−6x+10-4x^2+4x+20+x^2+3=0`

Combine all like terms.
`3x^2−6x+15−6x+10-4x^2+4x+20+x^2+3=0`
`3x^2-4x^2+x^2-6x-6x+4x+15+10+20+3=0`
`-8x+48=0`

Isolate `x`.
`-8x+48=0`
`-8x=-48`
`color(red)(x=6)`