# How do you solve (3 / (x^2 - 4)) = (2 / (x+2)) + (x / (x-2))?

Roots are real ; $x = 1.317 , x = - 5.317 \left(3 \mathrm{dp}\right)$
$\frac{3}{{x}^{2} - 4} = \frac{2 \left(x - 2\right) + x \left(x + 2\right)}{{x}^{2} - 4}$or $2 x - 4 + {x}^{2} + 2 x - 3 = 0 \mathmr{and} {x}^{2} + 4 x - 7 = 0$This is a quadratic equation of form ax^2+bx+c; a=1 ; b=4; c=-7
roots are real as ${b}^{2} - 4 a c$ is positive. Roots are $- \frac{b}{2 a} \pm \frac{\sqrt{{b}^{2} - 4 a c}}{2 a} = - \frac{4}{2} \pm \frac{\sqrt{44}}{2} = 1.317 , - 5.317$[Ans]