How do you solve #3(x-2)ln2=99#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Konstantinos Michailidis Sep 10, 2015 #x=2+33/ln2# Explanation: Well we have that #3(x-2)*ln2=99=>(x-2)=99/(3ln2)=>x-2=33/ln2=>x=2+33/ln2# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1255 views around the world You can reuse this answer Creative Commons License