How do you solve #3/(x-3)=x/(x-3)-3/2#?

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Answer 1 · 2018-03-03T13:56:13

No solutions for #x#

First subtract #3/(x-3) # from both sides:

#0 = x/(x-3) - 3/(x-3) -3/2 #

Simplifying:

#0 = (x-3)/(x-3) - 3/2 #

We can cancel, the #(x-3) # as it is on both bottom and top

#0 = cancel((x-3))/cancel((x-3)) - 3/2 #

#=> 0 = 1-3/2 #

#=> 0 = -1/2 #

But we know this is not true, so hence there are no solutions to this problem!