How do you solve #3(x-5)=12#?

2 Answers
May 3, 2018

Answer:

#x=9#

Explanation:

#"distribute the parenthesis on the left side of the equation"#

#3x-15=12#

#"add 15 to both sides"#

#3xcancel(-15)cancel(+15)=12+15#

#rArr3x=27#

#"divide both sides by 3"#

#(cancel(3) x)/cancel(3)=27/3#

#rArrx=9#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#3(9-5)=3xx4=12#

#rArrx=9" is the solution"#

May 3, 2018

Answer:

Isolate x
(answer will be nine)

Explanation:

First you want to divide both sides by 3

#(cancel3(x-5))/cancel3=12/3#

#x-5=4#

Add 5 to both sides

#x-cancel5+cancel5=4+5#

#x=9#