How do you solve #3(x-5)=6#?

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Answer 1 · 2016-11-16T22:58:26

#x = 7#

Step 1) Expand the terms in parenthesis, in this case only on the left side of the equation:

#3x - 15 = 6#

Step 2) Solve for #x# using the necessary mathematics while keeping the equation balanced:

#3x - 15 + 15 = 6 + 15#

#3x - 0 = 21#

#3x = 21#

#(3x)/3 = 21/3#

#x = 7#