# How do you solve -3(x + 6)^2 = 18?

Jul 30, 2015

$x = - 6 + \sqrt{6} i , - 6 - \sqrt{6} i$

#### Explanation:

$- 3 {\left(x + 6\right)}^{2} = 18$

Divide both sides by $- 3$.

${\left(x + 6\right)}^{2} = \frac{18}{-} 3$ =

${\left(x + 6\right)}^{2} = - 6$

Take the square root of both sides.

$x + 6 = \pm \sqrt{- 6}$

Subtract $6$ from both sides.

$x = - 6 \pm \sqrt{- 6}$

Solve for $x$.

$x = - 6 + \sqrt{6} i$

$x = - 6 - \sqrt{6} i$