How do you solve #-3(x + 6)^2 = 18#?

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Answer 1 · 2015-07-30T00:32:16

#x=-6+sqrt6 i, -6-sqrt 6 i#

#-3(x+6)^2=18#

Divide both sides by #-3#.

#(x+6)^2=18/-3# =

#(x+6)^2=-6#

Take the square root of both sides.

#x+6=+-sqrt(-6)#

Subtract #6# from both sides.

#x=-6+-sqrt(-6)#

Solve for #x#.

#x=-6+sqrt6i#

#x=-6-sqrt6i#