Question

How do you solve `3^x = 7`?

Answer 1

x ≈ 1.77

Explanation:

Using the following ' rule of logs '

`• logx^n = nlogx`

Take log of both sides. We can use log to any base. I'll use ln which is the `log_e`

hence `ln3^x = ln7`

using the rule from above : `xln3 = ln7 → x = ln7/ln3 ≈ 1.77`