How do you solve #32^(1-2X) = 8^(1/3)#?

Question

1552 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-19T06:28:38

#color(blue)(X=2/5#

#32^(1-2X)=8^(1/3#

We know that #32=2^5# and #8=2^3#

#2^(5(1-2X))=2^(3/3#

#2^(5(1-2X))=2^1#

Now as bases are equal we equate the powers

#5(1-2X) = 1#

#5-10X = 1#

#5-1 = 10X#

#4=10X#
#X=4/10#
#color(blue)(X=2/5#