How do you solve #-32-3/5f=-17#?

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Answer 1 · 2017-02-07T05:02:17

See the entire solution process below:

Step 1) Add #color(red)(32)# to each side of the equation to isolate the #f# term while keeping the equation balanced:

#-32 - 3/5f + color(red)(32) = -17 + color(red)(32)#

#-32 + color(red)(32) - 3/5f = 15#

#0 - 3/5f = 15#

#-3/5f = 15#

Step 2) Multiply each side of the equation by #-color(red)(5)/color(blue)(3)# to solve for #f# while keeping the equation balanced:

#-color(red)(5)/color(blue)(3) xx -3/5f = -color(red)(5)/color(blue)(3) xx 15#

#cancel(-color(red)(5))/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(-3)))/color(red)(cancel(color(black)(5)))f = -75/color(blue)(3)#

#f = -25#