# How do you solve 35=w(w-2) ?

Mar 19, 2016

The solution is $w = 7$ and $w = - 5$

#### Explanation:

Firstly change $35 = w \left(w - 2\right)$ into a standard form
So by factorizing

Expand the bracket

$35 = {w}^{2} - 2 w$

then put all terms on the left Hand side (LHS) and equate to zero,
So

${w}^{2} - 2 w - 35 = 0$

Now factor the quadratic by looking for a pair of factors of $- 35$ whose sum is $- 2$, which are $- 7$ and $5$:

$\left(w - 7\right) \left(w + 5\right) = 0$

For this to be true $w - 7 = 0$ or $w + 5 = 0$, so $w = 7$ or $w = - 5$.