# How do you solve #35=w(w-2) #?

##### 1 Answer

The solution is

#### Explanation:

Firstly change

So by factorizing

Expand the bracket

#35 = w^2 - 2w#

then put all terms on the left Hand side (LHS) and equate to zero,

So

#w^2 -2w -35 = 0#

Now factor the quadratic by looking for a pair of factors of

#(w -7)(w + 5) =0#

For this to be true