Question

How do you solve `35x^2+6x-9=0` using the quadratic formula?

Answer 1

`x_1=-6/10`
`x_2=3/7`

Explanation:

`"if an equation is given as "ax^2+bx+c=0;`
`"the quadratic formula is determined b y "x_"1,2"=(-b±sqrt(b^2-4*a*c))/(2*a)`

`35x^2+6x-9=0`
`a=35" ;"b=6" ;"c=-9`

`Delta=sqrt(b^2-4*a*c)=sqrt(6^2+4*35*9)`
`Delta=sqrt(36+1260)=sqrt1296`
`Delta=36`

`x_1=(-b-Delta)/(2*a)" "x_1=(-6-36)/(2*35)" "x_1=-42/70`

`x_1=-6/10`

`x_2=(-b+Delta)/(2*a)" "x_2=(-6+36)/(2*35)" "x_2=30/70" "x_2=3/7`