How do you solve #36^(x+2 )= 6^(3x-3)#?

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Answer 1 · 2015-07-22T16:01:29

#color(blue)(x=7#

#36^(x+2) = 6^(3x-3)#

#36=6^2#

The expression becomes:

#6^(2*(x+2)) = 6^(3x-3)#

#6^(2x+4)= 6^(3x-3)#

Now, since the bases are equal, we equate their respective powers:

#2x+4 = 3x-3#

#x = 4+3#

#color(blue)(x=7#