How do you solve #-3j - (-4)/-6 = 12#?

1 Answer
Jul 7, 2015

Answer:

I found: #j=-38/9#

Explanation:

Remember that #(-4)/-6=4/6=# (dividing top and bottom by #2#) #=2/3#. So you get:
#-3j-2/3=12# let us use #3# as common denominator:
#(-9j-2)/3=36/3# where I had to change the numerators that didn't have the #3#;
cancel the denominators:
#(-9j-2)/cancel(3)=36/cancel(3)#
#-9j-2=36# take the #2# to the right:
#-9j=36+2#
#-9j=38# divide by #-9# both sides:
#j=-38/9#