How do you solve #(3k)/27=2/3#?

1 Answer
Mar 12, 2017

Answer:

See the entire solution process below:

Explanation:

Multiply each side of the equation by #color(red)(27)/color(blue)(3)# to solve for #k# while keeping the equation balanced:

#color(red)(27)/color(blue)(3) xx (3k)/27 = color(red)(27)/color(blue)(3) xx 2/3#

#cancel(color(red)(27))/cancel(color(blue)(3)) xx (color(blue)(cancel(color(black)(3)))k)/color(red)(cancel(color(black)(27))) = (color(red)(27) xx 2)/(color(blue)(3) xx 3)#

#k = (color(red)(27) xx 2)/9#

#k = (cancel(color(red)(27))3 xx 2)/color(red)(cancel(color(black)(9)))#

#k = 6#