Question

How do you solve `3ln(x-3)+4=5`?

Answer 1

`x = root(3)(e) + 3`

Explanation:

Isolate the log

`3ln(x-3) = 5-4`
`ln(x-3) = 1/3`

Take the exponential from both sides, i.e.: the sideth power of e

`x-3 = e^(1/3) = root(3)(e)`

Isolate x

`x = root(3)(e) + 3`