How do you solve #3ln5x=10#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer MathFact-orials.blogspot.com Jan 7, 2017 #x=(e^(10/3))/5~~5.606# Explanation: #3ln(5x)=10# #ln(5x)=10/3# #e^ln(5x)=e^(10/3)# #5x=e^(10/3)# #x=(e^(10/3))/5~~5.606# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3572 views around the world You can reuse this answer Creative Commons License