How do you solve 3log_10 x+1 = 13? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Cesareo R. May 25, 2016 x=10^4 Explanation: 3log_{10}x+1=log_{10}x^3+log_{10}10=13=log_{10}10^{13} or equivalently log_{10}(10*x^3) = log_{10}10^{13} or equivalently 10*x^3=10^{13} concluding that x^3 = 10^{12}->x=10^4 Answer link Related questions What is the exponential form of log_b 35=3? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is log_b 1? What are some identity rules for logarithms? What is log_b b^x? What is the reciprocal of log_b a? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1702 views around the world You can reuse this answer Creative Commons License