How do you solve #3log_10 x+1 = 13#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Cesareo R. May 25, 2016 #x=10^4# Explanation: #3log_{10}x+1=log_{10}x^3+log_{10}10=13=log_{10}10^{13}# or equivalently #log_{10}(10*x^3) = log_{10}10^{13}# or equivalently #10*x^3=10^{13}# concluding that #x^3 = 10^{12}->x=10^4# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1532 views around the world You can reuse this answer Creative Commons License