# How do you solve 3log2x=4?

Mar 25, 2018

$x = \left(\frac{1}{2}\right) \cdot {10}^{\frac{4}{3}}$

#### Explanation:

Assuming the logarithm as Common Logarithm (With base $10$),

$\textcolor{w h i t e}{\times x} 3 \log 2 x = 4$

$\Rightarrow \log 2 x = \frac{4}{3}$ [Transposing The 3 to R.H.S.]

$\Rightarrow 2 x = {10}^{\frac{4}{3}}$ [According to The Definition of Logarithm]

$\Rightarrow x = \left(\frac{1}{2}\right) \cdot {10}^{\frac{4}{3}}$ [Transposing 2 to R.H.S]

Hope this helps.