How do you solve (3n+2)(n-2)=0?

Apr 23, 2017

$n = - \frac{2}{3}$ and $n = 2$

Explanation:

$\left(3 n + 2\right) \left(n - 2 = 0\right)$

:.$3 n + 2 = 0$ and $n - 2 = 0$

$\therefore 3 n = - 2$, $n = - \frac{2}{3}$ and $n = 2$

$\therefore n = - \frac{2}{3}$ and $n = 2$