Question

How do you solve `3u ^ { 2} + 3= - 10u`?

Answer 1

`u=-1/3` or `u=-3`

Explanation:

`3u^2+3=-10u`

so `3u^2+10u+3=0`

so `(3u+1)(u+3)=0`

so `3u+1=0` or `u+3=0`

so `u=-1/3` or `u=-3`