How do you solve #(3x-1)/3-(x-3)/15=(2x+3)/2#?
Isolate the first part:
Get the denominator (both bottom numbers) equal buy multiplying the tops and bottoms. 15 is a common multiple of 3 and 15 so multiply the first fraction by 5 and the second by 1.
Put it back in the whole equation:
Both have a common multiple of 30, so, multiply the first part by 2 and the second by 15.