How do you solve $(- 3 x) + 11 = 2$ $(-3x)+11=2$ ?

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Answer 1 · 2017-06-11T00:44:53

See a solution process below:

Step 1) Subtract $11$ $color(red)(11)$ from each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$(- 3 x) + 11 - 11 = 2 - 11$ $(-3x) + 11 - color(red)(11) = 2 - color(red)(11)$

$(- 3 x) + 0 = - 9$ $(-3x) + 0 = -9$

$- 3 x = - 9$ $-3x = -9$

Step 2) Divide each side of the equation by $- 3$ $color(red)(-3)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{- 3 x}{- 3} = \frac{- 9}{- 3}$ $(-3x)/color(red)(-3) = (-9)/color(red)(-3)$

$(color(red)(cancel(color(black)(-3)))x)/cancel(color(red)(-3)) = 3$

$x = 3$

How do you solve (-3x)+11=2(−3x)+11=2(-3x)+11=2?