# How do you solve #3x^2 - 10 = 2x# by completing the square?

##### 1 Answer

May 10, 2016

- Move the constant to the right
- Make a = 1
- Add on
#(b/2)^2# to both sides - Write as (x +- b/2)^2 =
- Find square toot of both sides
- Solve twice - pos and neg square root