# How do you solve 3x^2 – 10x + 5 = 0 using the quadratic formula?

Apr 5, 2018

$\frac{10 \pm \sqrt{40}}{6}$

#### Explanation:

$3 {x}^{2} - 10 x + 5 = 0$

It’s in the form of

$a {x}^{2} + b x + c = 0$

Comparing two equations

• $a = 3$
• $b = - 10$
• $c = 5$

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
x = (-(-10) +- sqrt((-10)^2 - (4 × 3 × 5)))/(2 × 3)
$x = \frac{10 \pm \sqrt{100 - 60}}{6}$
$x = \frac{10 \pm \sqrt{40}}{6}$