How do you solve #3x^2 – 10x + 5 = 0# using the quadratic formula?

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Answer 1 · 2018-04-05T04:00:30

#(10 +- sqrt(40))/6#

#3x^2 - 10x + 5 = 0#

It’s in the form of

#ax^2 + bx + c = 0#

Comparing two equations

#a = 3#

#b = -10#

#c = 5#

#x = (-b +- sqrt(b^2 - 4ac))/(2a)#

#x = (-(-10) +- sqrt((-10)^2 - (4 × 3 × 5)))/(2 × 3)#

#x = (10 +- sqrt(100 - 60))/6#

#x = (10 +- sqrt(40))/6#